Difference between revisions of "Viscosity and molecular properties"
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− | * '''Relationship between velocity gradient and strain rate:''' Viscosity can be understood from the following thought experiment. Say that a liquid is sandwiched between a static plane (z=0) and a plane (z=L) moving at a speed v. In a steady state, the liquid immediately near the moving plane will be moving at v, while the liquid near the static plane will not be moving. Assuming that the fluid is well-behaved (i.e. "linear"), the velocity will be a linear function of z: v(z) = \dot{\gamma} z, where \dot{\gamma} is the shear rate. Thus we can see that the shear rate, in addition to being the time-derivative of the shear, is dv/dz. | + | * '''Relationship between velocity gradient and strain rate:''' Viscosity can be understood from the following thought experiment. Say that a liquid is sandwiched between a static plane (z=0) and a plane (z=L) moving at a speed v. In a steady state, the liquid immediately near the moving plane will be moving at v, while the liquid near the static plane will not be moving. Assuming that the fluid is well-behaved (i.e. "linear"), the velocity will be a linear function of z: v(z) = \dot{\gamma} z, where \dot{\gamma} is the shear rate. Thus we can see that the shear rate, in addition to being the time-derivative of the shear, is dv/dz. To see the connection between dv/dz and d\gamma/dt, consider looking at a cube of liquid in the flow. Because the top of the cube is flowing faster than the bottom, the cube will be stretched into a parallelpiped. This stretching will increase with time; the top will be moving at speed h*(dv/dz) with respect to the bottom, thus after time t the stretching is t*h*(dv/dz). The strain is then t*(dv/dz), and thus the strain rate is dv/dz as claimed. |
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− | To see the connection between dv/dz and d\gamma/dt, consider looking at a cube of liquid in the flow. Because the top of the cube is flowing faster than the bottom, the cube will be stretched into a parallelpiped. This stretching will increase with time; the top will be moving at speed h*(dv/dz) with respect to the bottom, thus after time t the stretching is t*h*(dv/dz). The strain is then t*(dv/dz), and thus the strain rate is dv/dz as claimed. | + | |
== Viscosity and energy == | == Viscosity and energy == |
Revision as of 17:05, 21 September 2008
Viscosity
- Relationship between velocity gradient and strain rate: Viscosity can be understood from the following thought experiment. Say that a liquid is sandwiched between a static plane (z=0) and a plane (z=L) moving at a speed v. In a steady state, the liquid immediately near the moving plane will be moving at v, while the liquid near the static plane will not be moving. Assuming that the fluid is well-behaved (i.e. "linear"), the velocity will be a linear function of z: v(z) = \dot{\gamma} z, where \dot{\gamma} is the shear rate. Thus we can see that the shear rate, in addition to being the time-derivative of the shear, is dv/dz. To see the connection between dv/dz and d\gamma/dt, consider looking at a cube of liquid in the flow. Because the top of the cube is flowing faster than the bottom, the cube will be stretched into a parallelpiped. This stretching will increase with time; the top will be moving at speed h*(dv/dz) with respect to the bottom, thus after time t the stretching is t*h*(dv/dz). The strain is then t*(dv/dz), and thus the strain rate is dv/dz as claimed.
Viscosity and energy
Viscosity and molecular properties
Think of flow as repeated steps, stretch then relax: | |
The stress per step: | |
The elastic energy stored per unit volume is: | |
The work rate is the work divided by a relaxation time: |
We have calculated the work rate per unit volume from the viscosity and from the elasticity, including a characteristic time. Comparing them gives:
Work rate from the viscosity: | Work rate from the elascity: | Combining gives: |
The viscosity is related to the energy per unit volume and a relaxation time.