# Difference between revisions of "Drops, menisci, and lenses"

(New page: Back to Topics. == Equilibrium of a large drop == Small drops are spherical segments. Large drops are flattened. [[Image: DeGennes_Fig_2-4.gif|thumb|...) |
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[[Capillarity_and_wetting#Topics | Back to Topics.]] | [[Capillarity_and_wetting#Topics | Back to Topics.]] | ||

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Small drops are spherical segments. Large drops are flattened. | Small drops are spherical segments. Large drops are flattened. | ||

[[Image: DeGennes_Fig_2-4.gif|thumb| 400px | center | de Gennes, 2004, Fig. 2.4]] | [[Image: DeGennes_Fig_2-4.gif|thumb| 400px | center | de Gennes, 2004, Fig. 2.4]] |

## Revision as of 23:16, 27 September 2008

## Shape of a large drop

Small drops are spherical segments. Large drops are flattened.

To “spread” the drop requires an force per unit length:<math>\sigma _{sv}-\left( \sigma _{lv}+\sigma _{sl} \right)</math>

The hydrostatic pressure integrated over the depth of the drop is a force per unit length pushing to “spread” the drop: <math>\tilde{P}=\int\limits_{0}^{e}{\rho g\left( e-\tilde{z} \right)d\tilde{z}}=\frac{1}{2}\rho ge^{2}</math>

At equilibrium the sum of the two is zero: <math>\sigma _{sv}-\left( \sigma _{lv}+\sigma _{sl} \right)+\frac{1}{2}\rho ge^{2}=0</math>

Substituting the Young-Dupré equation: <math>\sigma _{lv}\left( 1-\cos \theta _{e} \right)=\frac{1}{2}\rho ge^{2}</math>

Re-arranging gives: <math>\text{ }e=2\kappa ^{-1}\sin \left( \frac{\theta _{e}}{2} \right)</math>